2j-j^2=1

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Solution for 2j-j^2=1 equation:


Simplifying
2j + -1j2 = 1

Solving
2j + -1j2 = 1

Solving for variable 'j'.

Reorder the terms:
-1 + 2j + -1j2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2j + -1j2 = 0

Factor a trinomial.
(-1 + j)(1 + -1j) = 0

Subproblem 1

Set the factor '(-1 + j)' equal to zero and attempt to solve: Simplifying -1 + j = 0 Solving -1 + j = 0 Move all terms containing j to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + j = 0 + 1 Combine like terms: -1 + 1 = 0 0 + j = 0 + 1 j = 0 + 1 Combine like terms: 0 + 1 = 1 j = 1 Simplifying j = 1

Subproblem 2

Set the factor '(1 + -1j)' equal to zero and attempt to solve: Simplifying 1 + -1j = 0 Solving 1 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1j = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1j = 0 + -1 -1j = 0 + -1 Combine like terms: 0 + -1 = -1 -1j = -1 Divide each side by '-1'. j = 1 Simplifying j = 1

Solution

j = {1, 1}

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